Quote:
Originally Posted by sunnypoker considering all the tens and 9s were gone
if 4 people hit trips, that means it was AKQJ on the board....
surely the 10 10 won then?? |
I'm not sure what you mean, sunny. Why do you say all the 10s and 9s were gone?
That said, there still aren't many possibilities for the hand's geometry.
Unless I'm mistaken, if four people got trips, that means the AA and KK could not have gotten trips unless the QQ player (who won) got a straight. Quads are not a possibility; that means the flop would have been Q-Q-x-x-x, which does not give us four players with trips, it only gives us three. In order for the QQ player to win with trips, it means AA and KK still could not have gotten trips, and the board had to have Q-J-10-9-x, with no possibility of a straight. If x was an 8, then only three players would have trips and QQ would have a straight, which is not what happened, according to the original post.
Or, maybe AA or KK did get trips, but QQ picked up a straight, with this flop: A-J-10-9-8. That would give four players trips and QQ would have a straight, beating the trips players.
A full house not a possibility. In order for QQ to get a full house, there must have either been trips on the board (which would give everyone a full house, and AA would have won) or there must have been a pair and a Q on the board (which would preclude four players from getting trips.)
From what I can tell, the only possibilities for QQ winning the hand are QQ picking up a Q high straight with the A-J-10-9-8 board or getting high trips with Q-J-10-9-x (x being something other than an 8.)
Does anyone see a flaw in this logic? If so, please tell me.